Selenium webdriver: How do I find ALL of an element's attributes?

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In the Python Selenium module, once I have a WebElement object I can get the value of any of its attributes with get_attribute():

foo = elem.get_attribute('href')

If the attribute named ‘href’ doesn’t exist, None is returned.

My question is, how can I get a list of all of the attributes that an element has? There doesn’t seem to be a get_attributes() or get_attribute_names() methods.

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It is not possible using a selenium webdriver API, but you can execute a javascript code to get all attributes:

driver.execute_script('var items = {}; for (index = 0; index < arguments[0].attributes.length; ++index) { items[arguments[0].attributes[index].name] = arguments[0].attributes[index].value }; return items;', element)

Demo:

>>> from selenium import webdriver
>>> from pprint import pprint
>>> driver = webdriver.Firefox()
>>> driver.get('https://stackoverflow.com')
>>>
>>> element = driver.find_element_by_xpath('//div[@class="network-items"]/a')
>>> attrs = driver.execute_script('var items = {}; for (index = 0; index < arguments[0].attributes.length; ++index) { items[arguments[0].attributes[index].name] = arguments[0].attributes[index].value }; return items;', element)
>>> pprint(attrs)
{u'class': u'topbar-icon icon-site-switcher yes-hover js-site-switcher-button js-gps-track',
u
'data-gps-track': u'site_switcher.show',
u
'href': u'//stackexchange.com',
u
'title': u'A list of all 132 Stack Exchange sites'}


For completeness sake, an alternative solution would be to get the tag’s outerHTML and parse the attributes using an HTML parser. Example (using BeautifulSoup):

>>> from bs4 import BeautifulSoup
>>> html = element.get_attribute('outerHTML')
>>> attrs = BeautifulSoup(html, 'html.parser').a.attrs
>>> pprint(attrs)
{u'class': [u'topbar-icon',
u
'icon-site-switcher',
u
'yes-hover',
u
'js-site-switcher-button',
u
'js-gps-track'],
u
'data-gps-track': u'site_switcher.show',
u
'href': u'//stackexchange.com',
u
'title': u'A list of all 132 Stack Exchange sites'}
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